NEETPhysicsLaws of MotionMCQ+4 / −1
A horizontal force is applied to a block as shown in figure. The mass of blocks and are and 3 respectively. The blocks slide over a frictionless surface. The force exerted by block on block is :
- AZero
- B4 N
- C6 N
- D10 N
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Correct answer: C
$$ \begin{aligned} & F=\left(M_1+M_2\right) a \\ & a=\frac{10}{2+3}=2 \mathrm{~ms}^{-2} \\ & F^{\prime}=M_2(2)=3 \times 2 \mathrm{~N}=6 \mathrm{~N} \end{aligned} $$
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