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Heat and Thermodynamics question

2020 · Q137
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Heat and Thermodynamics question

2020 · Q137

NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
The mean free path for a gas, with molecular diameter d and number density n can be expressed as :
  1. A
    12nπd2{1 \over {\sqrt 2 n\pi {d^2}}}2​nπd21​
  2. B
    12n2πd2{1 \over {\sqrt 2 {n^2}\pi {d^2}}}2​n2πd21​
  3. C
    12n2π2d2{1 \over {\sqrt 2 {n^2}{\pi ^2}{d^2}}}2​n2π2d21​
  4. D
    12nπd{1 \over {\sqrt 2 n\pi d}}2​nπd1​
View written solutionFree

Correct answer: A

As per the formula,
λ=12nπd2\lambda = {1 \over {\sqrt 2 n\pi {d^2}}}λ=2​nπd21​

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