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Heat and Thermodynamics question

2020 · Q138
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Heat and Thermodynamics question

2020 · Q138

NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
A cylinder contains hydrogen gas at pressure 249 kPa and temperature 27∘^\circ∘C
Its density is : (R = 8.3 J mol-1 K-1)
  1. A
    0.2 kg/m3
  2. B
    0.1 kg/m3
  3. C
    0.02 kg/m3
  4. D
    0.5 kg/m3
View written solutionFree

Correct answer: A

From the ideal gas equation, PV = nRT also
Volume (V) = mass(M)density(ρ){{mass(M)} \over {density(\rho )}}density(ρ)mass(M)​
So, PM = ρ\rho ρRT
P = 249 ×\times× 103 N/m2
M = 2 ×\times× 10-3 kg
T = 333 K
ρ\rho ρ = (249×103)(2×10−3)8.3×300{{\left( {249 \times {{10}^3}} \right)\left( {2 \times {{10}^{ - 3}}} \right)} \over {8.3 \times 300}}8.3×300(249×103)(2×10−3)​
= 0.2 kg/m3

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