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Heat and Thermodynamics question

2020 · Q129
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Heat and Thermodynamics question

2020 · Q129

NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
The average thermal energy for a mono-atomic gas is : (kB is Boltzmann constant and T absolute temperature)
  1. A
    32kBT{3 \over 2}{k_B}T23​kB​T
  2. B
    52kBT{5 \over 2}{k_B}T25​kB​T
  3. C
    72kBT{7 \over 2}{k_B}T27​kB​T
  4. D
    12kBT{1 \over 2}{k_B}T21​kB​T
View written solutionFree

Correct answer: A

The degree of freedom for monoatomic gas is 3. So, average thermal energy per molecule,
K.E.avg = 32kBT{3 \over 2}{k_B}T23​kB​T

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