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Heat and Thermodynamics question

2018 · Q150
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Heat and Thermodynamics question

2018 · Q150

NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
A sample of 0.1 g of water at 100°C and normal pressure (1.013 × 105 N m–2) requires 54 cal of heat energy to convert to steam at 100°C. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample, is
  1. A
    104.3 J
  2. B
    208.7 J
  3. C
    42.2 J
  4. D
    84.5 J
View written solutionFree

Correct answer: B

Using first law of thermodynamics,

Δ\Delta ΔQ = Δ\Delta ΔU + Δ\Delta ΔW

⇒\Rightarrow⇒ 54 × 4.18 = Δ\Delta ΔU + 1.013 × 105(167.1 × 10–6 – 0)

⇒\Rightarrow⇒ Δ\Delta ΔU = 208.7 J

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