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Heat and Thermodynamics question

2004 · Q154
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Heat and Thermodynamics question

2004 · Q154

NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
The equation of state for 5 g of oxygen at a pressure P and temperature T, when occupying a volume V, will be
(where R is the gas constant)
  1. A
    PV = (5/32)RT
  2. B
    PV = 5RT
  3. C
    PV = (5/2)RT
  4. D
    PV = (5/16) RT
View written solutionFree

Correct answer: A

As PV = nRT

n=mmolecular mass=532n = {m \over {molecular\,mass}} = {5 \over {32}}n=molecularmassm​=325​

⇒PV=(532)RT \Rightarrow PV = \left( {{5 \over {32}}} \right)RT⇒PV=(325​)RT

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