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Heat and Thermodynamics question

2000 · Q159
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Heat and Thermodynamics question

2000 · Q159

NEETPhysicsHeat and ThermodynamicsMCQ+4 / −1
To find out degree of freedom, the expansion is
  1. A
    f=2γ−1f = {2 \over {\gamma - 1}}f=γ−12​
  2. B
    f=γ+12f = {{\gamma + 1} \over 2}f=2γ+1​
  3. C
    f=2γ+1f = {2 \over {\gamma + 1}}f=γ+12​
  4. D
    f=1γ+1f = {1 \over {\gamma + 1}}f=γ+11​
View written solutionFree

Correct answer: A

γ=1+2f\gamma = 1 + {2 \over f}γ=1+f2​

where f is the degree of freedom

∴\therefore∴ 2f=γ−1⇒f=2γ−1{2 \over f} = \gamma - 1 \Rightarrow f = {2 \over {\gamma - 1}}f2​=γ−1⇒f=γ−12​

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