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Electrostatics question

2024 · Q187
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Electrostatics question

2024 · Q187

NEETPhysicsElectrostaticsMCQ+4 / −1

The value of electric potential at a distance of 9 cm9 \mathrm{~cm}9 cm from the point charge 4×10−7C4 \times 10^{-7} \mathrm{C}4×10−7C is [Given 14πε0=9×109 N m2C−2\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \mathrm{~N} \mathrm{~m}^2 \mathrm{C}^{-2}4πε0​1​=9×109 N m2C−2] :

  1. A
    4×102 V4 \times 10^2 \mathrm{~V}4×102 V
  2. B
    44.4 V44.4 \mathrm{~V}44.4 V
  3. C
    4.4×105 V4.4 \times 10^5 \mathrm{~V}4.4×105 V
  4. D
    4×104 V4 \times 10^4 \mathrm{~V}4×104 V
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