NEETPhysicsElectrostaticsMCQ+4 / −1
An electric dipole is placed as shown in the figure.

The electric potential (in 102 V) at point P due to the dipole is ( = permittivity of free space and = K) :
- A
- B
- C
- D
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Correct answer: D

$$\mathrm{v}=\frac{\mathrm{Kq}}{2 \times 10^{-2}}-\frac{\mathrm{Kq}}{8 \times 10^{-2}}$$
$$=\mathrm{Kq}\left[\frac{3}{8}\right] \times 10^{2}$$
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