NEETPhysicsElectrostaticsMCQ+4 / −1
The angle between the electric lines of force and the equipotential surface is
- A0
- B45
- C90
- D180
View written solutionFree
Correct answer: C
dV = $-$$\overrightarrow E $ . d$\overrightarrow r $
dV = $-$Edr cos$\theta$
For equipotential surface,
dV = 0
cos$\theta$ = 0
$\Rightarrow$ $\theta$ = 90$^\circ$
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