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Alternating Current question

2021 · Q128
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Alternating Current question

2021 · Q128

NEETPhysicsAlternating CurrentMCQ+4 / −1
An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance 'R' are connected in series to an ac source of potential difference 'V' volts as shown in figure. Potential difference across L, C and R is 40V, 10V and 40V, respectively. The amplitude of current flowing through LCR series circuit is 102\sqrt 22​ A. The impedance of the circuit is :

NEET 2021 Physics - Alternating Current Question 22 English
  1. A
    5Ω\OmegaΩ
  2. B
    42\sqrt 22​ Ω\OmegaΩ
  3. C
    5/2\sqrt 22​ Ω\OmegaΩ
  4. D
    4Ω\OmegaΩ
View written solutionFree

Correct answer: A

I0 = 102\sqrt 2 2​ A

IRMS = I2{I \over {\sqrt 2 }}2​I​ = 10A

VRMS=VR2+(VL−VC)2{V_{RMS}} = \sqrt {V_R^2 + {{({V_L} - {V_C})}^2}} VRMS​=VR2​+(VL​−VC​)2​

=(40)2+(40−10)2= \sqrt {{{(40)}^2} + {{(40 - 10)}^2}}=(40)2+(40−10)2​

= 50 V

Impedance, Z=VRMSIRM=50V10V=5ΩZ = {{{V_{RMS}}} \over {{I_{RM}}}} = {{50V} \over {10V}} = 5\Omega Z=IRM​VRMS​​=10V50V​=5Ω

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