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Structure of Atom question

2006 · Q110
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Structure of Atom question

2006 · Q110

NEETChemistryStructure of AtomMCQ+4 / −1
Given : The mass of electron is 9.11 ×\times× 10−-−31 kg, Planck constant is 6.626 ×\times× 10−-−34 J s, the uncertainty involved in the measurement of velocity within a distance of 0.1 A∘\mathop A\limits^ \circA∘​ is
  1. A
    5.79 ×\times× 105 m s−-−1
  2. B
    5.79 ×\times× 106 m s−-−1
  3. C
    5.79 ×\times× 107 m s−-−1
  4. D
    5.79 ×\times× 108 m s−-−1
View written solutionFree

Correct answer: B

Δx.mΔv=h/4π\Delta x.m\Delta v = h/4\pi Δx.mΔv=h/4π

0.1 ×\times× 10-10 ×\times× 9.11 ×\times× 10-31 ×\times× Δv\Delta vΔv = 6.626×10−344×3.143{{6.626 \times {{10}^{ - 34}}} \over {4 \times 3.143}}4×3.1436.626×10−34​

∴\therefore∴ Δv\Delta vΔv = 6.626×10−344×3.143×0.1×10−10×9.11×10−31{{6.626 \times {{10}^{ - 34}}} \over {4 \times 3.143 \times 0.1 \times {{10}^{ - 10}} \times 9.11 \times {{10}^{ - 31}}}}4×3.143×0.1×10−10×9.11×10−316.626×10−34​

= 5.79 ×\times× 106 m s-1

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