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Structure of Atom question

2000 · Q106
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Structure of Atom question

2000 · Q106

NEETChemistryStructure of AtomMCQ+4 / −1
For given energy, E = 3.03 ×\times× 10−-−19 Joules corresponding wavelength is (h = 6.626 ×\times× 10−-−34 J sec, c = 3 ×\times× 108 m/sec)
  1. A
    65.6 nm
  2. B
    6.56 nm
  3. C
    3.4 nm
  4. D
    656 nm
View written solutionFree

Correct answer: D

E = hcλ{{hc} \over \lambda }λhc​

⇒λ\Rightarrow \lambda⇒λ = 6.6×10−34×3×1083.03×10−19{{6.6 \times {{10}^{ - 34}} \times 3 \times {{10}^8}} \over {3.03 \times {{10}^{ - 19}}}}3.03×10−196.6×10−34×3×108​

= 656 nm

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