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Structure of Atom question

2005 · Q84
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Structure of Atom question

2005 · Q84

NEETChemistryStructure of AtomMCQ+4 / −1
The energy of second Bohr orbit of the hydrogen atom is −-−328 kJ mol−-−1; hence the energy of fourth Bohr orbit would be
  1. A
    −-− 41 kJ mol−-−1
  2. B
    −-−82 kJ mol−-−1
  3. C
    −-−164 kJ mol−-−1
  4. D
    −-−1312 kJ mol−-−1
View written solutionFree

Correct answer: B

En = -K(Zn)2{\left( {{Z \over n}} \right)^2}(nZ​)2

Z = 1; n = 2

E2 = { {{-K \times 1 \over 4}}}$$$ \Rightarrow $ E<sub>2</sub> = -328 kJ mol<sup>-1</sup>;<br><br> K = 4 $ \times $ 328<br><br> E<sub>4</sub> = { {{-K \times 1 \over 16}}}$$ ⇒\Rightarrow⇒ E4 = -4 ×\times× 328 116{ {{ 1 \over 16}}}161​

= -82 kJ mol-1

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