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Structure of Atom question

2003 · Q110
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Structure of Atom question

2003 · Q110

NEETChemistryStructure of AtomMCQ+4 / −1
The velocity of Planck's constant is 6.63 ×\times× 10−-−34 J s.

The velocity of light is 3.0 ×\times× 108 m s−-−1. Which value is closest to the wavelength in nanometers of a quantum of light with frequency of 8 ×\times× 1015 s−-−1 ?
  1. A
    2 ×\times× 10−-−25
  2. B
    5 ×\times× 10−-−18
  3. C
    4×1014 \times {10^1}4×101
  4. D
    3 ×\times× 107
View written solutionFree

Correct answer: C

vvv = c/λ\lambda λ

λ\lambda λ = cv{c \over v}vc​ = 3×1088×1015{{3 \times {{10}^8}} \over {8 \times {{10}^{15}}}}8×10153×108​ = 37.5 ×\times× 10-9 m

= 37.5 nm ≈\approx≈ 4×1014 \times {10^1}4×101 nm

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