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Ionic Equilibrum question

2009 · Q119
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Ionic Equilibrum question

2009 · Q119

NEETChemistryIonic EquilibrumMCQ+4 / −1
The ionization constant of ammonium hydroxide is 1.77 ×\times× 10−-−5 at 298 K. Hydrolysis constant of ammonium chloride is
  1. A
    6.50 ×\times× 10−-−12
  2. B
    5.65 ×\times× 10−-−13
  3. C
    5.65 ×\times× 10−-−12
  4. D
    5.65 ×\times× 10−-−10
View written solutionFree

Correct answer: D

Ammonium chloride is a salt of weak base and strong acid. In this case hydrolysis constant Kh can be calculated as

Kh = KwKb{{{K_w}} \over {{K_b}}}Kb​Kw​​ = 10−141.77×10−5{{{{10}^{ - 14}}} \over {1.77 \times {{10}^{ - 5}}}}1.77×10−510−14​ = 5.65 ×\times× 10−-−10

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