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Ionic Equilibrum question

2008 · Q118
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Ionic Equilibrum question

2008 · Q118

NEETChemistryIonic EquilibrumMCQ+4 / −1
Equal volumes of three acid solutions of pH 3, 4 and 5 are mixed in a vessel. What will be the H+ ion concentration in the mixture?
  1. A
    3.7 ×\times× 10−-−3 M
  2. B
    1.11 ×\times× 10−-−3 M
  3. C
    1.11 ×\times× 10−-−4 M
  4. D
    3.7 ×\times× 10−-−4 M
View written solutionFree

Correct answer: D

We know, pH = – log[H+]

For pH = 3, 3 = – log [H+]

⇒\Rightarrow⇒ [H+] = 10–3 M

For pH = 4 , 4 = – log [H+]

⇒\Rightarrow⇒ [H+] = 10–4 M

For pH = 5, 5 = – log [H+]

⇒\Rightarrow⇒ [H+] = 10–5 M

Total concentration of [H+]

M = 10−3(1+0.1+0.01)3{{{{10}^{ - 3}}\left( {1 + 0.1 + 0.01} \right)} \over 3}310−3(1+0.1+0.01)​

M(V1 +V2 + V3) = M1V1 + M2V2 + M3V3

As V1 = V2 = V3 = V

⇒\Rightarrow⇒M(3V) = (M1 + M2 + M3)V

⇒\Rightarrow⇒ 3M = (10–3 + 10–4 + 10–5)

= 1.11×10−33{{1.11 \times {{10}^{ - 3}}} \over 3}31.11×10−3​

= 3.7 ×\times× 10−-−4 M

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