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Ionic Equilibrum question

2009 · Q109
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Ionic Equilibrum question

2009 · Q109

NEETChemistryIonic EquilibrumMCQ+4 / −1
What is the [OH−-−] in the final solution prepared by mixing 20.0 mL of 0.050 M HCl with 30.0 mL of 0.10 M Ba(OH)2?
  1. A
    0.40 M
  2. B
    0.0050 M
  3. C
    0.12 M
  4. D
    0.10 M
View written solutionFree

Correct answer: D

Number of equivalents of H+ = 20.0 × 0.050 milliequivalents

= 1.0 milliequivalents

Number of equivalents of OH– = 2 × 30.0 × 0.10

= 6.0 milliequivalents

∴\therefore∴ Equivalents of OH- left after neutralization

= 6 – 1 = 5 milliequivalents

Total volume after neutralization

= 20.0 + 30.0 mL

= 50 mL

[OH-] = 550{5 \over {50}}505​ = 0.1 M

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