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Electrochemistry question

2008 · Q97
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Electrochemistry question

2008 · Q97

NEETChemistryElectrochemistryMCQ+4 / −1
On the basis of the following Eo values, the strongest oxidizing agent is
[Fe(CN)6]4−-− →\to→ [Fe(CN)6]3−-− + e−-−;  Eo = −-−0.35 V

Fe2+ →\to→ Fe3+ + e−-−;  Eo = −-−0.77 V
  1. A
    Fe3+
  2. B
    [Fe(CN)6]3−-−
  3. C
    [Fe(CN)6]4−-−
  4. D
    Fe2+
View written solutionFree

Correct answer: A

Substances which have higher reduction potential are stronger oxidizing agent.

[Fe(CN)6]4−-− →\to→ [Fe(CN)6]3−-− + e−-−;  Eo = −-−0.35 V

Fe2+ →\to→ Fe3+ + e−-−;  Eo = −-−0.77 V

Higher the +ve reduction potential, stronger will be the oxidising agent. Oxidising agent oxidises other compounds and gets itself reduced easily.

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