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Coordination Compounds question

2009 · Q108
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Coordination Compounds question

2009 · Q108

NEETChemistryCoordination CompoundsMCQ+4 / −1
Out of TiF62−-−, CoF63−-−, Cu2Cl2 and NiCl42−-− (Z of Ti = 22, Co = 27, Cu = 29, Ni = 28) the colourless species are
  1. A
    Cu2Cl2 and NiCl42−-−
  2. B
    TiF62−-− and Cu2Cl2
  3. C
    CoF63−-− and NiCl42−-−
  4. D
    TiF62−-− and CoF63−-−
View written solutionFree

Correct answer: B

In TiF62–, Ti is present as Ti+4

Ti+4 = [Ar] 3d0 4s0

Hence, TiF62– is colourless due to empty d orbital.

In Cu2Cl2, Cu is present as Cu+

Cu+ = [Ar] 3d10 4s0

Due to absence of unpaired electrons, Cu2Cl2 is colourless.

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