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Coordination Compounds question

2006 · Q85
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Coordination Compounds question

2006 · Q85

NEETChemistryCoordination CompoundsMCQ+4 / −1
[Cr(H2O)6]Cl3 (At. no. of Cr = 24) has a magnetic momen of 3.83 B.M. The correct distribution of 3d electrons in the chromium of the complex is
  1. A
    3dx y1, 3dy z1, 3dz213d_{x\,y}^1,\,3d_{y\,z}^1,\,3d_{z^2}^{1}3dxy1​,3dyz1​,3dz21​
  2. B
    3d(x2−y2)1, 3dz21, 3dxz13d_{\left( {x^2 - y^2} \right)}^1,\,3d_{z^2}^1,\,3d_{xz}^13d(x2−y2)1​,3dz21​,3dxz1​
  3. C
    3dx y1,  3d(x2−y2)1, 3dy z13d_{x\,y}^1,\,\,3d_{\left( {x^2 - y^2} \right)}^1,\,3d_{y\,z}^13dxy1​,3d(x2−y2)1​,3dyz1​
  4. D
    3dx y1, 3dy z1, 3dx z13d_{x\,y}^1,\,3d_{y\,z}^1,\,3d_{x\,z}^13dxy1​,3dyz1​,3dxz1​
View written solutionFree

Correct answer: D

3.83 = n(n+2)\sqrt {n\left( {n + 2} \right)} n(n+2)​

⇒\Rightarrow⇒ n = 3

Thus, number of unpaired electrons in d-orbitals subshells of chromium (Cr = 24) = 3

∴\therefore∴ Configuration of Cr = 1s2 2s2 2p6 3s2 3p6 3d3

In 3d3 the distribution of electrons

3dx y1, 3dy z1, 3dx z13d_{x\,y}^1,\,3d_{y\,z}^1,\,3d_{x\,z}^13dxy1​,3dyz1​,3dxz1​, 3dx2−y20,3dz203d_{{x^2} - {y^2}}^0,3d_{{z^2}}^03dx2−y20​,3dz20​

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