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Coordination Compounds question

2008 · Q86
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Coordination Compounds question

2008 · Q86

NEETChemistryCoordination CompoundsMCQ+4 / −1
Which of the following complexes exhibits the highest paramagnetic behaviour?
where gly = glycine, en = ethylenediamine and bpy = bipyridyl moities.
(At. nos. Ti = 22, V = 23, Fe = 26, Co = 27)
  1. A
    [Co(ox)2(OH)2]−-−
  2. B
    [Ti(NH3)6]3+
  3. C
    [V(gly)2(OH)2(NH3)2]+
  4. D
    [Fe(en)(bpy)(NH3)2]2+
View written solutionFree

Correct answer: A

In [Co(ox)2(OH)2]−-−

Co+5 = [Ar] 3d4 (4 unpaired electrons)

OX and OH are weak field ligands.

In [Ti(NH3)6]3+

Ti+3 = [Ar] 3d1 (one unpaired electron)

In [V(gly)2(OH)2(NH3)2]+


V+5 = [Ar] 4r03d0 (no unpaired electron)

In [Fe(en)(bpy)(NH3)2]2+

Fe+2 = [Ar] 3d6 (4 unpaired electrons)

But due to presence of strong field ligand like NH3, bpy and en thus Fe+2 contains no unpaired electron.

∴\therefore∴ Complex [Co(ox)2(OH)2]−-− has maximum number of unpaired electrons, thus show maximum paramagnetism.

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