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Chemical Kinetics question

2009 · Q99
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Chemical Kinetics question

2009 · Q99

NEETChemistryChemical KineticsMCQ+4 / −1
For the reaction, N2 + 3H2 →\to→ 2NH3, if
d[NH3]dt{{d\left[ {N{H_3}} \right]} \over {dt}}dtd[NH3​]​ = 2 ×\times× 10−-−4 mol L−-−1 s−-−1,
the value of −d[H2]dt{{ - d\left[ {{H_2}} \right]} \over {dt}}dt−d[H2​]​ would be
  1. A
    4 ×\times× 10−-−4 mol L−-−1 s−-−1
  2. B
    6 ×\times× 10−-−4 mol L−-−1 s−-−1
  3. C
    1 ×\times× 10−-−4 mol L−-−1 s−-−1
  4. D
    3 ×\times× 10−-−4 mol L−-−1 s−-−1
View written solutionFree

Correct answer: D

N2 + 3H2 →\to→ 2NH3

−13d[H2]dt=12d[NH3]dt - {1 \over 3}{{d\left[ {{H_2}} \right]} \over {dt}} = {1 \over 2}{{d\left[ {N{H_3}} \right]} \over {dt}}−31​dtd[H2​]​=21​dtd[NH3​]​

⇒\Rightarrow⇒ −d[H2]dt=32d[NH3]dt - {{d\left[ {{H_2}} \right]} \over {dt}} = {3 \over 2}{{d\left[ {N{H_3}} \right]} \over {dt}}−dtd[H2​]​=23​dtd[NH3​]​

= 32×2×10−4{3 \over 2} \times 2 \times {10^{ - 4}}23​×2×10−4

= 3×10−43 \times {10^{ - 4}}3×10−4 mol L−-−1 s−-−1

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