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Chemical Kinetics question

2006 · Q100
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Chemical Kinetics question

2006 · Q100

NEETChemistryChemical KineticsMCQ+4 / −1
Consider the reaction :  N2(g) + 3H2(g) →\to→ 2NH3(g)

The equality relationship between d[NH3]dt{{d\left[ {N{H_3}} \right]} \over {dt}}dtd[NH3​]​ and −d[H2]dt- {{d\left[ {{H_2}} \right]} \over {dt}}−dtd[H2​]​ is
  1. A
    d[NH3]dt=−d[H2]dt{{d\left[ {N{H_3}} \right]} \over {dt}} = - {{d\left[ {{H_2}} \right]} \over {dt}}dtd[NH3​]​=−dtd[H2​]​
  2. B
    d[NH3]dt=−13d[H2]dt{{d\left[ {N{H_3}} \right]} \over {dt}} = - {1 \over 3}{{d\left[ {{H_2}} \right]} \over {dt}}dtd[NH3​]​=−31​dtd[H2​]​
  3. C
    +d[NH3]dt=−23d[H2]dt+ {{d\left[ {N{H_3}} \right]} \over {dt}} = - {2 \over 3}{{d\left[ {{H_2}} \right]} \over {dt}}+dtd[NH3​]​=−32​dtd[H2​]​
  4. D
    +d[NH3]dt=−32d[H2]dt+ {{d\left[ {N{H_3}} \right]} \over {dt}} = - {3 \over 2}{{d\left[ {{H_2}} \right]} \over {dt}}+dtd[NH3​]​=−23​dtd[H2​]​
View written solutionFree

Correct answer: C

N2(g) + 3H2(g) →\to→ 2NH3(g)

Rate = −d[N2]dt=−13d[H2]dt=12d[NH3]dt{{ - d\left[ {{N_2}} \right]} \over {dt}} = - {1 \over 3}{{d\left[ {{H_2}} \right]} \over {dt}} = {1 \over 2}{{d\left[ {N{H_3}} \right]} \over {dt}}dt−d[N2​]​=−31​dtd[H2​]​=21​dtd[NH3​]​

$ \Rightarrow $$${{d\left[ {N{H_3}} \right]} \over {dt}} = - {2 \over 3}{{d\left[ {{H_2}} \right]} \over {dt}}$$

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