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Chemical Kinetics question

2007 · Q88
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Chemical Kinetics question

2007 · Q88

NEETChemistryChemical KineticsMCQ+4 / −1
If 60% of a first order reaction was completed in 60 minutes, 50% of the same reaction would be completed in approximately
(log 4 = 0.60, log 5 = 0.69)
  1. A
    45 minutes
  2. B
    60 minutes
  3. C
    40 minutes
  4. D
    50 minutes
View written solutionFree

Correct answer: A

For a first order reaction,

k = 2.303tlog⁡aa−x{{2.303} \over t}\log {a \over {a - x}}t2.303​loga−xa​

k = 2.30360log⁡10040{{2.303} \over {60}}\log {{100} \over {40}}602.303​log40100​

= 2.30360log⁡2.5{{2.303} \over {60}}\log 2.5602.303​log2.5

= 0.0153

Also, t1/2{t_{1/2}}t1/2​ = 2.303klog⁡10050{{2.303} \over k}\log {{100} \over {50}}k2.303​log50100​

= 2.3030.0153log⁡2{{2.303} \over {0.0153}}\log 20.01532.303​log2

= 45 min.

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