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Chemical Bonding and Molecular Structure question

2002 · Q112
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Chemical Bonding and Molecular Structure question

2002 · Q112

NEETChemistryChemical Bonding and Molecular StructureMCQ+4 / −1
Which of the following is isoelectronic?
  1. A
    CO2, NO2
  2. B
    NO2−-−, CO2
  3. C
    CN−-−, CO
  4. D
    SO2, CO2
View written solutionFree

Correct answer: C

In CO, the number of electrons

⇒\Rightarrow⇒ 6 + 8 = 14 [ Z of C = 6 and O = 8]

Electronic configuration of molecular orbital of CO :

(σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2(π2px)2(π2py)2(π2pz)2{\left( {\sigma 1s} \right)^2}{\left( {{\sigma ^*}1s} \right)^2}{\left( {\sigma 2s} \right)^2}{\left( {{\sigma ^*}2s} \right)^2}{\left( {\pi 2{p_x}} \right)^2}{\left( {\pi 2{p_y}} \right)^2}{\left( {\pi 2{p_z}} \right)^2}(σ1s)2(σ∗1s)2(σ2s)2(σ∗2s)2(π2px​)2(π2py​)2(π2pz​)2

CN- also get (6 + 7 + 1) 14 electrons and the configuration is similar to that CO.

So, CN and CO is isoelectronic.

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