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Work Power and Energy question

2020 · 7 Jan · Shift 1 · Q46
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Work Power and Energy question

2020 · 7 Jan · Shift 1 · Q46

JEE MainPhysicsWork Power and EnergyNumerical+4 / −1
A particle (m = 1 kg) slides down a frictionless track (AOC) starting from rest at a point A (height 2 m). After reaching C, the particle continues to move freely in air as a projectile. When it reaching its highest point P (height 1 m), the kinetic energy of the particle (in )) is : (Figure drawn is schematic and not to scale; take g = 10 ms-2) JEE Main 2020 (Online) 7th January Morning Slot Physics - Work Power & Energy Question 99 English
Numerical answer
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Correct answer: 10

  1. Use conservation of mechanical energy on the frictionless track and during projectile motion

Since the track is frictionless and the particle moves freely under gravity afterward, total mechanical energy remains constant throughout the motion.

  1. Initial state at point AAA
  • Mass: m=1 kgm = 1\,\text{kg}m=1kg
  • Starts from rest, so initial kinetic energy: KA=0K_A = 0KA​=0
  • Height of AAA above reference level: hA=2 mh_A = 2\,\text{m}hA​=2m

So total energy at AAA is only potential energy: E=mghA=1⋅10⋅2=20 JE = mgh_A = 1 \cdot 10 \cdot 2 = 20\,\text{J}E=mghA​=1⋅10⋅2=20J

  1. State at highest point PPP

At the highest point of projectile motion, the height is given as: hP=1 mh_P = 1\,\text{m}hP​=1m

Potential energy at PPP: UP=mghP=1⋅10⋅1=10 JU_P = mgh_P = 1 \cdot 10 \cdot 1 = 10\,\text{J}UP​=mghP​=1⋅10⋅1=10J

  1. Find kinetic energy at PPP

By conservation of mechanical energy: KP+UP=EK_P + U_P = EKP​+UP​=E KP+10=20K_P + 10 = 20KP​+10=20 KP=10 JK_P = 10\,\text{J}KP​=10J

  1. Final answer

The kinetic energy of the particle at the highest point is: 10\boxed{10}10​

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