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Waves question

2025 · 23 Jan · Shift 2 · Q51
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Waves question

2025 · 23 Jan · Shift 2 · Q51

JEE MainPhysicsWavesMCQ+4 / −1
The equation of a transverse wave travelling along a string is y(x,t)=4.0sin⁡[20×10−3x+600t]mmy(x, t)=4.0 \sin \left[20 \times 10^{-3} x+600 t\right] \mathrm{mm}y(x,t)=4.0sin[20×10−3x+600t]mm, where xxx is in mm and ttt is in second. The velocity of the wave is :
  1. A
    −60 m/s-60 \mathrm{~m} / \mathrm{s}−60 m/s
  2. B
    +60 m/s+60 \mathrm{~m} / \mathrm{s}+60 m/s
  3. C
    +30 m/s+30 \mathrm{~m} / \mathrm{s}+30 m/s
  4. D
    −30 m/s-30 \mathrm{~m} / \mathrm{s}−30 m/s
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