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Waves question

2024 · 8 Apr · Shift 2 · Q80
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Waves question

2024 · 8 Apr · Shift 2 · Q80

JEE MainPhysicsWavesMCQ+4 / −1
A plane progressive wave is given by y=2cos⁡2π(330t−x)my=2 \cos 2 \pi(330 \mathrm{t}-x) \mathrm{m}y=2cos2π(330t−x)m. The frequency of the wave is :
  1. A
    660 Hz
  2. B
    340 Hz
  3. C
    330 Hz
  4. D
    165 Hz
View written solutionFree

Correct answer: C

  1. Write the given wave equation

    The wave is y=2cos⁡2π(330t−x) my = 2\cos 2\pi(330t - x)\,\text{m}y=2cos2π(330t−x)m

  2. Compare with the standard form

    The standard equation of a progressive wave is y=Acos⁡2π(ft−xλ)y = A\cos 2\pi(ft - \frac{x}{\lambda})y=Acos2π(ft−λx​)

    where:

    • AAA is amplitude
    • fff is frequency
    • λ\lambdaλ is wavelength
  3. Identify the frequency

    Given: y=2cos⁡2π(330t−x)y = 2\cos 2\pi(330t - x)y=2cos2π(330t−x)

    Comparing with y=Acos⁡2π(ft−xλ)y = A\cos 2\pi(ft - \frac{x}{\lambda})y=Acos2π(ft−λx​)

    we get f=330 Hzf = 330\,\text{Hz}f=330Hz

  4. Check options

    • A: 660 Hz660\,\text{Hz}660Hz ❌
    • B: 340 Hz340\,\text{Hz}340Hz ❌
    • C: 330 Hz330\,\text{Hz}330Hz ✅
    • D: 165 Hz165\,\text{Hz}165Hz ❌
  5. Final answer

    The frequency of the wave is 330 Hz\boxed{330\,\text{Hz}}330Hz​

  6. Comparison with stored answer

    Stored correct answer: C

    Our derived answer: C

    Hence, the answer agrees with the stored correct answer.

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