JEE MainPhysicsMotion in A Straight LineMCQ+4 / −1
A scooter accelerates from rest for time t1 at constant rate a1 and then retards at constant rate a2 for time t2 and comes to rest. The correct value of wil be :
- A
- B
- C
- D
View written solutionFree
Correct answer: C
- Motion during acceleration
The scooter starts from rest and accelerates with constant acceleration for time .
Using we get
So, the velocity after the first phase is
- Motion during retardation
Now the scooter slows down with constant retardation for time and finally comes to rest.
Here initial velocity for this phase is , final velocity is , and acceleration is .
Again using
Thus,
- Find the ratio
- Match with options
Option C is which matches our result.
Therefore, the correct answer is Option C.
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