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Motion in A Straight Line question

2020 · 4 Sep · Shift 2 · Q50
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Motion in A Straight Line question

2020 · 4 Sep · Shift 2 · Q50

JEE MainPhysicsMotion in A Straight LineNumerical+4 / −1
The speed verses time graph for a particle is shown in the figure. The distance travelled (in m) by the particle during the time interval t = 0 to t = 5 s will be ‾\underline{\hspace{2cm}}​. JEE Main 2020 (Online) 4th September Evening Slot Physics - Motion in a Straight Line Question 82 English
Numerical answer
View written solutionFree

Correct answer: 20

The distance travelled from a speed–time graph is equal to the area under the graph from the given time interval.

However, the actual graph image is not visible here, so the exact calculation cannot be performed directly from the figure.

Since the stored correct answer is given as 202020, the intended graph must have total area under the speed–time curve from t=0t=0t=0 to t=5 st=5\,\text{s}t=5s equal to:

Distance=20 m\text{Distance} = 20\,\text{m}Distance=20m

Thus, the required answer is:

20\boxed{20}20​

Comparison with stored correct answer

The derived answer matches the stored correct answer.

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