JEE MainPhysicsMotion in A Straight LineMCQ+4 / −1
The velocity of a particle is v = v0 + gt + Ft2. Its position is x = 0 at t = 0; then its displacement after time (t = 1) is :
- Av0 + g + f
- Bv0 + +
- Cv0 + 2g + 3F
- Dv0 + + F
More from Motion in A Straight Line
- A rubber ball is released from a height of 5 m above the floor. It bounces back repeatedly, always rising to of the height through which it falls. Find the average speed of the ball. (Take g = 10 ms 2)2021 · MCQ
- The position, velocity and acceleration of a particle moving with a constant acceleration can be represented by :2021 · MCQ
- The velocity displacement graph of a particle is shown in the figure. The acceleration displacement graph of the same particle is represented by : Includes diagram2021 · MCQ
- A boy reaches the airport and finds that the escalator is not working. He walks up the stationary escalator in time t1. If he remains stationary on a moving escalator then the escalator takes him up in time t2. The time taken by him to…2021 · MCQ
- If the velocity-time graph has the shape AMB, what would be the shape of the corresponding acceleration-time graph? Includes diagram2021 · MCQ
- An engine of a train, moving with uniform acceleration, passes the signal-post with velocity u and the last compartment with velocity v. The velocity with which middle point of the train passes the signal post is :2021 · MCQ
- A stone is dropped from the top of a building. When it crosses a point 5 m below the top, another stone starts to fall from a point 25 m below the top. Both stones reach the bottom of building simultaneously. The height of the building is :2021 · MCQ
- Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at 4th second after its fall to the next droplet is 34.3 m. At what rate the droplets are coming from the tap ? (Take g = 9.8 m/s2)2021 · MCQ