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Heat and Thermodynamics question

2024 · 5 Apr · Shift 2 · Q80

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JEE Main
Physics
Heat and Thermodynamics
2024 · 5 Apr · Shift 2 · Q80

Heat and Thermodynamics question

2024 · 5 Apr · Shift 2 · Q80

JEE MainPhysicsHeat and ThermodynamicsMCQ+4 / −1

If

\mathrm{n}

is the number density and

\mathrm{d}

is the diameter of the molecule, then the average distance covered by a molecule between two successive collisions (i.e. mean free path) is represented by :

A
$\frac{1}{\sqrt{2} \mathrm{n} \pi \mathrm{d}^2}$
B
$\frac{1}{\sqrt{2} n^2 \pi^2 d^2}$
C
$\frac{1}{\sqrt{2 n \pi d^2}}$
D
$\sqrt{2} \mathrm{n} \pi \mathrm{d}^2$

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