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Heat and Thermodynamics question

2024 · 8 Apr · Shift 1 · Q80
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Heat and Thermodynamics question

2024 · 8 Apr · Shift 1 · Q80

JEE MainPhysicsHeat and ThermodynamicsMCQ+4 / −1
Two different adiabatic paths for the same gas intersect two isothermal curves as shown in P-V diagram. The relation between the ratio VaVd\frac{V_a}{V_d}Vd​Va​​ and the ratio VbVc\frac{V_b}{V_c}Vc​Vb​​ is: JEE Main 2024 (Online) 8th April Morning Shift Physics - Heat and Thermodynamics Question 60 English
  1. A
    VaVdeqVbVc\frac{V_a}{V_d} eq \frac{V_b}{V_c}Vd​Va​​eqVc​Vb​​
  2. B
    VaVd=(VbVc)−1\frac{V_a}{V_d}=\left(\frac{V_b}{V_c}\right)^{-1}Vd​Va​​=(Vc​Vb​​)−1
  3. C
    VaVd=VbVc\frac{V_a}{V_d}=\frac{V_b}{V_c}Vd​Va​​=Vc​Vb​​
  4. D
    VaVd=(VbVc)2\frac{V_a}{V_d}=\left(\frac{V_b}{V_c}\right)^2Vd​Va​​=(Vc​Vb​​)2
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