JEE MainPhysicsHeat and ThermodynamicsNumerical+4 / −1
The total internal energy of two mole monoatomic ideal gas at temperature T = 300 K will be J. (Given R = 8.31 J/mol.K)
Numerical answer
More from Heat and Thermodynamics
- A sample of an ideal gas is taken through the cyclic process ABCA as shown in figure. It absorbs, 40 J of heat during the part AB, no heat during BC and rejects 60 J of heat during CA. A work of 50 J is done on the gas during the part BC.… Includes diagram2022 · MCQ
- What will be the effect on the root mean square velocity of oxygen molecules if the temperature is doubled and oxygen molecule dissociates into atomic oxygen?2022 · MCQ
- The pressure and density of diatomic gas changes suddenly to and respectively during an adiabatic…2022 · Numerical
- One mole of a monoatomic gas is mixed with three moles of a diatomic gas. The molecular specific heat of mixture at constant volume is ; then the value of …2022 · Numerical
- A thermodynamic system is taken from an original state D to an intermediate state E by the linear process shown in the figure. Its volume is then reduced to the original volume from E to F by an isobaric process. The total work done by the… Includes diagram2022 · MCQ
- The root mean square speed of smoke particles of mass in their Brownian motion in air at NTP is approximately. [Given ]2022 · MCQ
- A cylinder of fixed capacity of 44.8 litres contains helium gas at standard temperature and pressure. The amount of heat needed to raise the temperature of gas in the cylinder by 20.0 C will be : (Given gas constant R = 8.3 JK …2022 · MCQ
- In van der Waal equation [V b] = RT; P is pressure, V is volume, R is universal gas constant and T is temperature. The ratio of constants is dimensionally equal to :2022 · MCQ