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Heat and Thermodynamics question

2021 · 26 Feb · Shift 2 · Q71
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Heat and Thermodynamics question

2021 · 26 Feb · Shift 2 · Q71

JEE MainPhysicsHeat and ThermodynamicsNumerical+4 / −1
The volume V of a given mass of monoatomic gas changes with temperature T according to the relation V=KT23V = K{T^{{2 \over 3}}}V=KT32​. The workdone when temperature changes by 90K will be xR. The value of x is ‾\underline{\hspace{2cm}}​. [R = universal gas constant]
Numerical answer
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