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Electrostatics question

2025 · 28 Jan · Shift 2 · Q73
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Electrostatics question

2025 · 28 Jan · Shift 2 · Q73

JEE MainPhysicsElectrostaticsNumerical+4 / −1
An electric dipole of dipole moment 6×10−6Cm6 \times 10^{-6} \mathrm{Cm}6×10−6Cm is placed in uniform electric field of magnitude 106V/m10^{6} \mathrm{V} / \mathrm{m}106V/m. Initially, the dipole moment is parallel to electric field. The work that needs to be done on the dipole to make its dipole moment opposite to the field, will be ‾\underline{\hspace{2cm}}​ J.
Numerical answer
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