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Electrostatics question

2024 · 9 Apr · Shift 2 · Q82

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2024 · 9 Apr · Shift 2 · Q82

Electrostatics question

2024 · 9 Apr · Shift 2 · Q82

JEE MainPhysicsElectrostaticsNumerical+4 / −1

An electric field

\vec{E}=(2 x \hat{i}) N C^{-1}

exists in space. A cube of side

2 \mathrm{~m}

is placed in the space as per figure given below. The electric flux through the cube is

\underline{\hspace{2cm}}

\mathrm{Nm}^2 / \mathrm{C}

.

JEE Main 2024 (Online) 9th April Evening Shift Physics - Electrostatics Question 51 English

Numerical answer

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