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Electrostatics question

2024 · 27 Jan · Shift 2 · Q86
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Electrostatics question

2024 · 27 Jan · Shift 2 · Q86

JEE MainPhysicsElectrostaticsNumerical+4 / −1
The electric potential at the surface of an atomic nucleus (z=50)(z=50)(z=50) of radius 9×10−13 cm9 \times 10^{-13} \mathrm{~cm}9×10−13 cm is ‾\underline{\hspace{2cm}}​×106 V\times 10^6 \mathrm{~V}×106 V.
Numerical answer
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