JEE MainPhysicsElectrostaticsMCQ+4 / −1
Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R). Assertion (A) : Work done by electric field on moving a positive charge on an equipotential surface is always zero. Reason (R) : Electric lines of forces are always perpendicular to equipotential surfaces. In the light of the above statements, choose the most appropriate answer from the options given below :
- ABoth (A) and (R) are correct and (R) is the correct explanation of (A)
- B(A) is correct but (R) is not correct
- CBoth (A) and (R) are correct but (R) is not the correct explanation of (A)
- D(A) is not correct but (R) is correct
More from Electrostatics
- Two charges of and are placed at the points and located in an electric field …2024 · Numerical
- The electric potential at the surface of an atomic nucleus of radius is .2024 · Numerical
- Two charges of and are situated at the points and respectively. The electric flux through a sphere of radius '' having center at origin is :2024 · MCQ
- An electron is moving under the influence of the electric field of a uniformly charged infinite plane sheet having surface charge density . The electron at is at a distance of from and has a…2024 · Numerical
- An electric field is given by . The electric flux through a surface area lying in YZ-plane (in SI unit) is :2024 · MCQ
- The electrostatic potential due to an electric dipole at a distance '' varies as :2024 · MCQ
- A particle of charge '' and mass '' moves in a circle of radius '' around an infinitely long line charge of linear charge density ''. Then time period will be given as : (Consider as Coulomb's constant)2024 · MCQ
- Two identical charged spheres are suspended by strings of equal lengths. The strings make an angle of with each other. When suspended in a liquid of density , the angle remains same. If density…2024 · Numerical