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Electrostatics question

2020 · 8 Jan · Shift 1 · Q40
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Electrostatics question

2020 · 8 Jan · Shift 1 · Q40

JEE MainPhysicsElectrostaticsMCQ+4 / −1
In finding the electric field using Gauss Law the formula ∣E→∣=qencε0∣A∣\left| {\overrightarrow E } \right| = {{{q_{enc}}} \over {{\varepsilon _0}\left| A \right|}}​E​=ε0​∣A∣qenc​​ is applicable. In the formula ε0{{\varepsilon _0}}ε0​ is permittivity of free space, A is the area of Gaussian surface and qenc is charge enclosed by the Gaussian surface. The equation can be used in which of the following situation?
  1. A
    Only when ∣E→∣\left| {\overrightarrow E } \right|​E​ = constant on the surface.
  2. B
    For any choice of Gaussian surface.
  3. C
    Only when the Gaussian surface is an equipotential surface.
  4. D
    Only when the Gaussian surface is an equipotential surface and ∣E→∣\left| {\overrightarrow E } \right|​E​ is constant on the surface.
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