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Electrostatics question

2020 · 9 Jan · Shift 1 · Q50
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Electrostatics question

2020 · 9 Jan · Shift 1 · Q50

JEE MainPhysicsElectrostaticsMCQ+4 / −1
An electric dipole of moment p→=(−i^−3j^+2k^)×10−29\overrightarrow p = \left( { - \widehat i - 3\widehat j + 2\widehat k} \right) \times {10^{ - 29}}p​=(−i−3j​+2k)×10−29 C.m is at the origin (0, 0, 0). The electric field due to this dipole at r→=+i^+3j^+5k^\overrightarrow r = + \widehat i + 3\widehat j + 5\widehat kr=+i+3j​+5k(note that r→.p→=0\overrightarrow r .\overrightarrow p = 0r.p​=0 ) is parallel to :
  1. A
    (+i^+3j^−2k^)\left( { + \widehat i + 3\widehat j - 2\widehat k} \right)(+i+3j​−2k)
  2. B
    (+i^−3j^−2k^)\left( { + \widehat i - 3\widehat j - 2\widehat k} \right)(+i−3j​−2k)
  3. C
    (−i^+3j^−2k^)\left( { - \widehat i + 3\widehat j - 2\widehat k} \right)(−i+3j​−2k)
  4. D
    (−i^−3j^+2k^)\left( { - \widehat i - 3\widehat j + 2\widehat k} \right)(−i−3j​+2k)
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