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Electronic Devices question

2019 · 12 Apr · Shift 1 · Q53
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Electronic Devices question

2019 · 12 Apr · Shift 1 · Q53

JEE MainPhysicsElectronic DevicesMCQ+4 / −1
The truth table for the circuit given in the fig. is: JEE Main 2019 (Online) 12th April Morning Slot Physics - Semiconductor Question 159 English
  1. A
    ∣ABY001011101111∣\left| {\begin{matrix} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \end{matrix} } \right|​A0011​B0101​Y1111​​
  2. B
    ∣ABY001010100110∣\left| {\begin{matrix} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \\ \end{matrix} } \right|​A0011​B0101​Y1000​​
  3. C
    ∣ABY001011100110∣\left| {\begin{matrix} A & B & Y \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \\ \end{matrix} } \right|​A0011​B0101​Y1100​​
  4. D
    ∣ABY000010101111∣\left| {\begin{matrix} A & B & Y \\ 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \\ \end{matrix} } \right|​A0011​B0101​Y0011​​
View written solutionFree

Correct answer: C

  1. The given options correspond to standard two-input logic truth tables. Let us identify them:
  • Option A: output is always 111.
  • Option B: output is 111 only for A=0,B=0A=0, B=0A=0,B=0. This is the truth table of a NOR gate: Y=A+B‾Y=\overline{A+B}Y=A+B​
  • Option C: output is 111 whenever A=0A=0A=0, independent of BBB. So, Y=A‾Y=\overline{A}Y=A
  • Option D: output follows AAA only, independent of BBB. So, Y=AY=AY=A
  1. From the circuit in the figure, the output corresponds to inversion of input AAA, while input BBB does not affect the final output.

Hence, Y=A‾Y=\overline{A}Y=A

  1. Now write the truth table for Y=A‾Y=\overline{A}Y=A:
A & B & Y \\ \hline 0 & 0 & 1 \\ \hline 0 & 1 & 1 \\ \hline 1 & 0 & 0 \\ \hline 1 & 1 & 0 \\ \hline \end{array}$$ 4. This matches **Option C**. Therefore, the correct answer is **C**.
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