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Electromagnetic Waves question

2021 · 31 Aug · Shift 2 · Q54
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  5. /2021 · 31 Aug · Shift 2 · Q54

Electromagnetic Waves question

2021 · 31 Aug · Shift 2 · Q54

JEE MainPhysicsElectromagnetic WavesMCQ+4 / −1
The magnetic field vector of an electromagnetic wave is given by B=B0i^+j^2cos⁡(kz−ωt)B = {B_0}{{\widehat i + \widehat j} \over {\sqrt 2 }}\cos (kz - \omega t)B=B0​2​i+j​​cos(kz−ωt); where i^,j^\widehat i,\widehat ji,j​ represents unit vector along x and y-axis respectively. At t = 0s, two electric charges q1 of 4 π\piπ coulomb and q2 of 2 π\piπ coulomb located at (0,0,πk)\left( {0,0,{\pi \over k}} \right)(0,0,kπ​) and (0,0,3πk)\left( {0,0,{{3\pi } \over k}} \right)(0,0,k3π​), respectively, have the same velocity of 0.5 c i^\widehat ii, (where c is the velocity of light). The ratio of the force acting on charge q1 to q2 is :-
  1. A
    22:12\sqrt 2 :122​:1
  2. B
    1:21:\sqrt 21:2​
  3. C
    2 : 1
  4. D
    2:1\sqrt 2 :12​:1
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