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Electromagnetic Waves question

2020 · 3 Sep · Shift 1 · Q62
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  5. /2020 · 3 Sep · Shift 1 · Q62

Electromagnetic Waves question

2020 · 3 Sep · Shift 1 · Q62

JEE MainPhysicsElectromagnetic WavesMCQ+4 / −1
The magnetic field of a plane electromagnetic wave is B→=3×10−8sin⁡[200π(y+ct)]i^\overrightarrow B = 3 \times {10^{ - 8}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat iB=3×10−8sin[200π(y+ct)]i T where c = 3 ×\times× 108 ms–1 is the speed of light. The corresponding electric field is :
  1. A
    E→=−10−6sin⁡[200π(y+ct)]k^\overrightarrow E = - {10^{ - 6}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat kE=−10−6sin[200π(y+ct)]k V/m
  2. B
    E→=−9sin⁡[200π(y+ct)]k^\overrightarrow E = - 9\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat kE=−9sin[200π(y+ct)]k V/m
  3. C
    E→=9sin⁡[200π(y+ct)]k^\overrightarrow E = 9\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat kE=9sin[200π(y+ct)]k V/m
  4. D
    E→=3×10−8sin⁡[200π(y+ct)]k^\overrightarrow E = 3 \times {10^{ - 8}}\sin \left[ {200\pi \left( {y + ct} \right)} \right]\widehat kE=3×10−8sin[200π(y+ct)]k
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