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Electromagnetic Waves question

2020 · 5 Sep · Shift 2 · Q49
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  5. /2020 · 5 Sep · Shift 2 · Q49

Electromagnetic Waves question

2020 · 5 Sep · Shift 2 · Q49

JEE MainPhysicsElectromagnetic WavesMCQ+4 / −1
The correct match between the entries in column I and column II are :

I II
Radiation Wavelength
(a) Microwave (i) 100 m
(b) Gamma rays (ii) 10–15 m
(c) A.M. radio waves (iii) 10–10 m
(d) X-rays (iv) 10–3 m
  1. A
    (a)-(ii), (b)-(i), (c)-(iv), (d)-(iii)
  2. B
    (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
  3. C
    (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
  4. D
    (a)-(i), (b)-(iii), (c)-(iv), (d)-(ii)
View written solutionFree

Correct answer: B

  1. Recall the approximate wavelength ranges of the given radiations

    • A.M. radio waves have very large wavelengths, typically of the order of meters to hundreds of meters.
    • Microwaves have wavelengths of the order of 10−3 m10^{-3}\,\text{m}10−3m to 10−1 m10^{-1}\,\text{m}10−1m.
    • X-rays have wavelengths of the order of 10−10 m10^{-10}\,\text{m}10−10m.
    • Gamma rays have even smaller wavelengths, typically of the order of 10−15 m10^{-15}\,\text{m}10−15m.

  2. Match each radiation with the given wavelength

    Column II gives:

    • (i) 100 m100\,\text{m}100m
    • (ii) 10−15 m10^{-15}\,\text{m}10−15m
    • (iii) 10−10 m10^{-10}\,\text{m}10−10m
    • (iv) 10−3 m10^{-3}\,\text{m}10−3m

    Now match:

    • (a) Microwave →10−3 m\rightarrow 10^{-3}\,\text{m}→10−3m, so (a)-(iv)
    • (b) Gamma rays →10−15 m\rightarrow 10^{-15}\,\text{m}→10−15m, so (b)-(ii)
    • (c) A.M. radio waves →100 m\rightarrow 100\,\text{m}→100m, so (c)-(i)
    • (d) X-rays →10−10 m\rightarrow 10^{-10}\,\text{m}→10−10m, so (d)-(iii)

  3. Compare with the options

    The matching obtained is:

    (a)−(iv),(b)−(ii),(c)−(i),(d)−(iii)(a)-(iv),\quad (b)-(ii),\quad (c)-(i),\quad (d)-(iii)(a)−(iv),(b)−(ii),(c)−(i),(d)−(iii)

    This corresponds to Option B.

  4. Verification with stored answer

    Stored correct answer = B

    Our derived answer = B

    Hence, they agree.

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