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Electromagnetic Waves question

2020 · 3 Sep · Shift 2 · Q48
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Electromagnetic Waves question

2020 · 3 Sep · Shift 2 · Q48

JEE MainPhysicsElectromagnetic WavesMCQ+4 / −1
The electric field of a plane electromagnetic wave propagating along the x direction in vacuum is E→=E0j^cos⁡(ωt−kx)\overrightarrow E = {E_0}\widehat j\cos \left( {\omega t - kx} \right)E=E0​j​cos(ωt−kx). The magnetic field B→\overrightarrow BB , at the moment t = 0 is :
  1. A
    B→=E0μ0∈0cos⁡(kx)j^\overrightarrow B = {{{E_0}} \over {\sqrt {{\mu _0}{ \in _0}} }}\cos \left( {kx} \right)\widehat jB=μ0​∈0​​E0​​cos(kx)j​
  2. B
    B→=E0μ0∈0cos⁡(kx)k^\overrightarrow B = {{{E_0}} \over {\sqrt {{\mu _0}{ \in _0}} }}\cos \left( {kx} \right)\widehat kB=μ0​∈0​​E0​​cos(kx)k
  3. C
    B→=E0μ0∈0cos⁡(kx)k^\overrightarrow B = {E_0}\sqrt {{\mu _0}{ \in _0}} \cos \left( {kx} \right)\widehat kB=E0​μ0​∈0​​cos(kx)k
  4. D
    B→=E0μ0∈0cos⁡(kx)j^\overrightarrow B = {E_0}\sqrt {{\mu _0}{ \in _0}} \cos \left( {kx} \right)\widehat jB=E0​μ0​∈0​​cos(kx)j​
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