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Electromagnetic Waves question

2020 · 7 Jan · Shift 2 · Q46

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JEE Main
Physics
Electromagnetic Waves
2020 · 7 Jan · Shift 2 · Q46

Electromagnetic Waves question

2020 · 7 Jan · Shift 2 · Q46

JEE MainPhysicsElectromagnetic WavesMCQ+4 / −1

The electric field of a plane electromagnetic wave is given by

\overrightarrow E = {E_0}{{\widehat i + \widehat j} \over {\sqrt 2 }}\cos \left( {kz + \omega t} \right)

At t = 0, a positively charged particle is at the point (x, y, z) =

\left( {0,0,{\pi \over k}} \right)

. If its instantaneous velocity at (t = 0) is

{v_0}\widehat k

, the force acting on it due to the wave is :

A
parallel to $\widehat k$
B
parallel to ${{\widehat i + \widehat j} \over {\sqrt 2 }}$
C
antiparallel to ${{\widehat i + \widehat j} \over {\sqrt 2 }}$
D
zero

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