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Electromagnetic Waves question

2019 · 9 Apr · Shift 1 · Q50
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Electromagnetic Waves question

2019 · 9 Apr · Shift 1 · Q50

JEE MainPhysicsElectromagnetic WavesMCQ+4 / −1
The magnetic field of a plane electromagnetic wave is given by : B‾=B0i^[cos⁡(kz−ωt)]+Bij^cos⁡(kz+ωt)\overline B = {B_0}\widehat i\left[ {\cos (kz - \omega t)} \right] + {B_i}\widehat j\cos (kz + \omega t)B=B0​i[cos(kz−ωt)]+Bi​j​cos(kz+ωt) B0 = 3 × 10–5 T and B1 = 2 × 10–6 T. The rms value of the force experienced by a stationary charge Q = 10–4 C at z = 0 is closest to :
  1. A
    0.6 N
  2. B
    0.9 N
  3. C
    3 × 10–2 N
  4. D
    0.1 N
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