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Current Electricity question

2024 · 30 Jan · Shift 1 · Q82
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Current Electricity question

2024 · 30 Jan · Shift 1 · Q82

JEE MainPhysicsCurrent ElectricityNumerical+4 / −1
Two cells are connected in opposition as shown. Cell E1\mathrm{E}_1E1​ is of 8 V8 \mathrm{~V}8 V emf and 2Ω2 \Omega2Ω internal resistance; the cell E2\mathrm{E}_2E2​ is of 2 V2 \mathrm{~V}2 V emf and 4Ω4 \Omega4Ω internal resistance. The terminal potential difference of cell E2\mathrm{E}_2E2​ is ‾\underline{\hspace{2cm}}​ V. JEE Main 2024 (Online) 30th January Morning Shift Physics - Current Electricity Question 46 English
Numerical answer
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